Correct Answer - C
On combining the two vessels the total number of moes remains constant , `i.e., n = n_(1)+n_(2)`
Using gas equation, we can write , `n_(1) +(P_(1)V)/(RT_(1)), n_(2) = (P_(2)V)/(RT_(2))`
and `n=(P(2V))/(RT)`
where `V` is the volume of each vessel.
Thus `(P(2V))/(RT) = (P_(1)V)/(RT_1)+(P_(2)V)/(RT_2) or P/T = 1/2[(P_1)/(T_1)+(P_2)/(T_2)]` .