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The `P - V` diagram of a system undergoing thermodynamic transformation is shown in figure. The work done by the system in going from `A rarr B rarr C is 30 J` and `40 J` heat is given to the system. The change in internal energy between `A and C` is
image
A. `10 J`
B. `70 J`
C. `84 J`
D. `134 J`

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Correct Answer - A
Heat given `DeltaQ =40J` and work done `DeltaW = 30J`
`implies DeltaQ=DeltaQ-DeltaW = 40-30 = 10J`.

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