Question

A tyre pumped to a pressure `3.375 atm "at" 27^(@)C` suddenly bursts. What is the final temperature `(gamma = 1.5)`?
A. `27^(@)C`
B. `-27^(@)C`
C. `0^(@)C`
D. `-73^(@)C`

Answer 1

Correct Answer - D
`T_(1)^(1-gamma) P_(1)^(1-gamma) =T_(2)^(gamma) P_(2)^(1-gamma)`
or `((T_1)/(T_2))^(gamma) = ((P_1)/(P_2))^(gamma-1) = ((300)/(T_2))^(3//2) = (3.375/1)^(3//2-1)`
OR, `T_(2) = (300)/((3.375)^(1//3)) = 200K = -73^(@)C`.