Question

A worker pushes a wheelbarrow with a horizontal force of `50 N` on level ground over a distance of `5.0 m`. If a friction force on the `43 N` acts on the wheelbarrow in a direction opposite that to of worker, what work is done on the wheelbarrow by the worker?
A. `250 J`
B. `215 J`
C. `35 J`
D. `10 J`

Answer 1

Correct Answer - A
The work done on the wheebarrow by the worker is `W = (F cos theta) Delta x = (50 N) (5.0 m) = + 250 J`