Question

A uniform chain of length `L` and mass `M` is tying on a smoth table and one third of its length is banging vertically down table the edge of the table if g is acceleration the to gravity , the work required to pull the hanging part on the table is
A. `MgL`
B. `(MgL)/(3)`
C. `(MgL)/(9)`
D. `(MgL)/(18)`

Answer 1

Correct Answer - D
The weight of hanging part `((L)/(3))` from the table
As work done = force `xx` distance
`:. W = (Mg)/(3) xx (L)/(6) = (MgL)/(18)`