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A stationary partical explodes into two partical of a masses `m_(1) and m_(2)` which move in opposite direction with velocities `v_(1) and v_(2)`. The ratio of their kinetic energies `E_(1)//E_(2)` is
A. `m_(1)//m_(2)`
B. 1
C. `m_(1)v_(2)//m_(2)v_(1)`
D. `m_(2)//m_(1)`

1 Answer

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Best answer
`E = (P^(2))/(2m) implies E prop (1)/(m) implies (E_(1))/(E_(2)) = (m_(2))/(m_(1))`

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