Question

A wheel of radius `1 m` rolls forward half a revolution on a horizontal ground. The magnitude of the displacement of the point of the wheel initially on contact with the ground is.
A. `pi`
B. `2 pi`
C. `sqrt(2) pi`
D. `sqrt(pi^2 + 4)`

Answer 1

Correct Answer - D
(d) Linear distance moved by wheel in half revolution `= pi r`. Point `P_1` afte half revolution reaches at `P_2` vertically `2 m` above the fround.
:. Displacement `P_1 P_2`
=`sqrt(pi^2 r^2 + 2^2) = sqrt(pi^2 + 4) [because r = 1 m]`.
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