Correct Answer - D
(d) Moment of inertia of disc passing through its centre of gravity and perpendicular to its plane is.
`I_(AB) = (1)/(2) MR^2`
Using theorem of parallel axes, we have,
`I_(CD) = I_(AB) + MR^2`
=`(1)/(2) MR^2 + MR^2 = (3)/(2) MR^2`.
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