Question

Two differenent liqiud of masses 10g and 20 g and density `0.84 g//c c` and `0.95 g//c c` are mixed toghther. Find the density of the mixture.

Answer 1

Here, `m_(1)=10g, m_(2)=20g, rho_(1)=0.84g//c c , rho_(2)=0.95 g//c c`.
Volume of first liquid, `V_(1)=(m_1)/(rho_1) = (10)/(0.84)c c`.
Volume of second liquid, `V_(2)=(m_2)/(rho_2) = (20)/(0.95) c c`.
Total volume `= V_(1)+V_(2) = (10)/(0.84) +(20)/(0.95)`
`:.` Density of mixture` = (m_(1)+m_(2))/(V_(1)+V_(2))=(10+20)/((10//0.84)+(20//0.95)) = (30)/(11.9+21.1) = (30)/(33.0) = 0.90 g//c c`.