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To lift an automobile of 2000 kg, a hydraulic pump with a large piston 30 cm square in area is employed. Calculate the force that must be applied to pump a small piston of area 10 square cm to achieve it.

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Here, `F_(2) = Mg = 2000 xx 9.8 = 19600 N`
`A_(2) = 30 x` cm square `= 30 xx 30 sq cm`
`= 900 xx 10^(-4)m^(2)`
As `(F_1)/(A_1) = (F_2)/(A_2)` so `F_(1) =(F_(2) xx A_(1))/(A_2)`
` = (19600 xx 10 xx 19^(-4))/(900 xx 10^(-4))`
`= 217.8 N`.

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