Question

The excess pressure inside a soap bubble is thrice the excess pressure inside a second soap bubble. What is the ratio between the volume of the first and the second bubble?

Answer 1

Given ` (4S)/(r_1) = (3 xx 4S)/(r^(2)) or r_(2) = 3 r_(1)` ,
`(V_1)/(V_2) = ((4//3) pi r_(1)^(3))/((4//3) pi r_(2)^(3)) = ((r_1)/(r_2))^(3) = (1/3)^(3) = 1/27`.