Question

There are two wires of same material and same length while the diameter of second wire is 2 times the diameter of first wire, then ratio of extension produced in the wires by applying same load will be
A. `1:1`
B. `2:1`
C. `1:2`
D. `4:1`

Answer 1

Correct Answer - D
`l=(FL)/(AY)` `because` `lprop(1)/(r^2)`
`(l_1)/(l_2)=((r_2)/(r_1))=(2)^2=4`