Here, diameter of the hose,
`D= 2.0 cm,`
Speed of water in the hose, `V=90.0 cms^(-1)`,
Diameter of each hole, `d= 0.125 cm`,
number of holes, `n=24` ltbr. Let `upsilon` be the velocity of water flowing out of each hole. Volume of the water crossing hose per second is equal to the volume of the water leaving out per second through holes : so,
`(pi D^2)/(4) xx V = npi d^(2)/(4) xx upsilon`
or `upsilon = (D^(2)V)/(nd^2) = ((2)^(2)xx 90.0)/(24 xx (0.125)^(2)) = 960 cm//s`.