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in Physics by (86.6k points)
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If work `W` is done in blowing a bubble of radius `R` from a soap solution. Then the work done is blowing a bubble of radius `2R` from the same solution is
A. `(W)/(2)`
B. `2W`
C. `4W`
D. `(7)/(3)W`

1 Answer

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Best answer
Correct Answer - C
`W=2xx4piR^2xxsigma`, R is increased by a factor of `2`. So, `W` is incresed bby a factor of `4`.

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