Question

The edges of an aluminum cube are `10 cm` long. One face of the cube is firmly fixed to a vertical wall. A mass of `100 kg` is then attached to the opposite face of the cube. Shear modulus of aluminum is `25 xx 10^(9) Pa`, the vertical deflection in the face to which mass is attached is

Answer 1

`A = 0.10 xx 0.10 = 10^(-2)m^(2) , F=mg =100 xx 10 N, G = 25 Gpa = 25 xx 10^(9) xx 1 Nm^(-2) = 25 xx 10^(9)Nm^(-2)`
Shearing strain = `(Delta L)/(L) = ((F//A))/(G) or Delta L = (FL)/(AG) = ((100 xx 10)xx 0.10)/(10^(-2)xx(25 xx 10^(9))) = 4 xx 10^(-7)m`.