A uniform rod of length 2.0 m specific gravity 0.5 and mass 2 kg is hinged at one end to the bottom of a tank of water (specific gravity = 10) filled upto a height o f 1.0 m as shown in figure. Taking the case `theta =- 0^(@)` the force exerted by the hings on the rod is `(g = 10 m//s^(2))`
A. 10.2 N upwards
B. 4.2 N downwards
C. 8.3 N downwards
D. 6.2 N upwards
