Question

`600` kg. of water is to be pumped in a tank per minute under the perssure of `10` g. wt//sq. mm. Find the horse power needed. `1 H.P.=746` watts.

Answer 1

Mass of water to be pumped, `m=600 kg`.
Volume of water to be pumped, `V=(mass)/(density)=(600)/(10^(3))=0.06 m^(3)`,
Pressure `=10` gwt//sq mm.
`(10)/(1000)xx9.8 N//(10^(3))^(2) sq m`
`=10xx9.8xx10^(3) N//m^(2)`
`Power=("workdone")/("time")=("pressure"xx"volume")/("time")`
`=((10xx9.8xx10^(3))xx0.6)/(60)=980 watt`
`(980)/(746)hp=1.31 hp`