Question

A glass flask of volume one litre at `0^(@)C` is filled, level full of mercury at this temperature. The flask and mercury are now heated to `100^(@)C`. How much mercury will spill out if coefficient of volume expansion of mercury is `1.82 xx 10^(-4)//^(@)C` and linear expansion of glass is `0.1 xx 10^(-4)//^(@)C` respectively?
A. `21.2 cc`
B. `15.2 cc`
C. `1.52 cc`
D. `2.12 cc`

Answer 1

Correct Answer - B
Due to volume expansion of both liquid and vessel, the change in volume of liquid relative to container is given by `Delta V = V_(0)[gamma_(L) -gamma_(g)]Delta theta`
Given `V_(0)=1000 c c, alpha_(g) = 0.1 xx 10^(-4)//^(@)C`
`:. gamma_(g) = 3 alpha_(g) = 3 xx 0.1 xx 10^(-4)//^(@)C = 0.3 xx 10^(-4)//^(@)C`
`:. Delta V = 1000 [1.82 xx 10^(-4)-0.3 xx 10^(-4)] xx 100`
`=15.2 c c`.