Question

It is required to prepare a steel metre scale, such that the millimetre intervals are to be ac curate within `0.0005 mm` at a certain temperature. Determine the maximum temperature variation allowable during the rulling of millimetre marks. Given, `alpha` for steel `=1.322xx10^(-5) .^(@)C^(-1)`

Answer 1

Correct Answer - `[37.8^(@) C]`
`Delta L=L alpha Delta T`
`Delta T=(Delta L)/(Lalpha)=(5xx10^(-4))/(1xx1.32xx10^(-5))=37.8^(@)C`