Correct Answer - `[1934 K, 1.5 mu m]`
Given, `P_(1) =P_(2)` , So `A sigma epsilon_(1) T_(1)^(4)=A sigma epsilon_(2) T_(2)^(4)`
or `T_(2)=T_(1) ((epsilon_(1))/(epsilon_(2)))^(1//4)`
`=5802 ((0.01)/(0.81))^(1//4) =5802xx(1)/(3) =1934 K`
or `1-(1)/(lambda_(2)) =(T_(2))/(T_(1))= (1934)/(5802)`
or `(1)/(lambda_(2))= 1- (1934)/(5802)= (3868)/(5802)`
or `lambda_(2)= (5802)/(3868)= 1.5 mu m`