Question

Calculate the amount of heat required to convert 5 g of ice of 0 °C into water at 0 °C. (Specific latent heat of fusion of ice = 80 cal/g)

Answer 1

Here, m = 5 g, L = 80 cal/g; Q = ?

Amount of heat required, Q = mL

= 5 g × 80 cal/g

= 400 calories.