Correct Answer - B
The resultant conductivity of combination of two rods ,
in parallel is, `K_(p) =K_(1) + K_(2) =K + K=2 K`
in secries is, `K_(s) =(K_(1)K_(2))/(K_(1) + K_(2)) = (KxxK)/(K+K) = (K)/(2)`
`q_(1) =((2K) A(100-0))/(x) = (2KAxx100)/(x)`
`q_(2) =((K)/(2)) (A(100-0))/(x) = (KAxx100)/(2x)`
`:. (q_(2))/(q_(1)) = (KAxx100)/(2x)xx(x)/(2KAxx100) =(1)/(4)`