Question

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A liquid flows through a horizontal tube. The velocities of the liquid in the two sections which have area of cross section `A_(1)` and `A_(2)` are `v_(1),v_(2)` respectively. The difference in the levels of liquid in the two vertical tubes is h.
A. the volume of liquid flowing through the tube in unit time is `A_(1)v_(1)`
B. `v_(2)-v_(1)=sqrt(2gh)`
C. `v_(2)^(2)=v_(1)^(2)=2gh`
D. the energy per unit mass of liquid is the same in both the sections of the tube.

Answer 1

Correct Answer - A::C::D
Rate of flow`=A_(1)V_(1)`
`(P_(1))/(rho)+(v_(1)^(2))/(2)=(P_(2))/(rho)+(v_(2)^(2))/(2)impliesP_(1)-P_(2)=(rho)/(2)(v_(2)^(2)-v_(1)^(2))`
`impliesv_(2)^(2)-v_(1)^(2)=2gh`
The energy per unit mass of the liquid is the same in both sections.