Question

A tube of length L and radius R is joinced to another tube of length `(L)/(3)` and radius `(R)/(2)`. A fluid is flowing through this joint tube. If the pressure difference across the first tube is `P` then pressure difference across the second tube is
A. `(16P)/(3)`
B. `(4P)/(3)`
C. `P`
D. `(3P)/(16)`

Answer 1

Correct Answer - 1
`(P_(1))/(P_(2))=(R_(1))/(R_(2))=(((8nl_(1))/(pir_(1)^(4))))/(((8nl_(2))/(pir_(2)^(4))))`