Correct Answer - `700J`
For a diatomic gas, `C_(v)=5/2R, C_(p)=7/2R`
In an isobaric process, work done
`W=p(V_(2)-V_(1))=nRT_(2)-nRT_(1)`
`=nR(T_(2)-T_(1))`
`:. T_(2)-T_(1)=W/(nR)`
Heat given in an isobaric process
`Q=nC_(p)(T_(2)-T_(1))=(nC_(p)W)/(nR)`
For diatomic gas, `C_(p)= 7/2R`
`=7/2 (RW)/(R)= 7/2xx200J= 700J`