Question

The flow of blood in a large artery of an anaeshetized dog is diverted through a venturimeter. The wider part of the meter has a cross sectional area equal to that of the artery i.e. `8 mm^(2)`. The narrower parts has an are `4 mm^(2)`. The pressure dorp in the artery is `24Pa`. what is the speed of the blood in the artery ? Given that density of the blood = `1.06 xx 10^(3) kg//m^(3)`

Answer 1

We take the density of blood from table `1.06xx10^(3)kgm^(-3)`. The ratio of the areas is `((A)/(a))=2`.
we obtain
`upsilon_(1)=sqrt((2xx24Pa)/(1060kgm^(-2)xx(2^(2)-1)))=0.123ms^(-1)`