here `r=2xx10^(-3)m,D=2r=2xx2xx10^(-3)=4xx10^(-3)m,`
`eta=2.084xx10^(-3)" "Pa-s," "rho=1.06xx10^(3)kgm^(-3)`
For flow to be laminar, `N_(R)=2000`
(a). Now, `v_(C)=(N_(R)eta)/(rhoD)=(2000xx(2.084xx10^(-3)))/((1.06xx10^(3))xx(4xx10^(-3)))=0.98m//s`.
(b). volume flowing per second `=pir^(2)v_(c)=(22)/(7)xx(2xx10^(-3))^(2)xx0.98=1.23xx10^(-5)m^(3)s^(-1)`