Correct Answer - A
Here k,Volume of wster heated =4 litre `mi n^(-1)` 1 litre =1000g,
then mass of water `=4xx1000g min ^(-1)=4000g mi n^(-1)`
Rise in temperature
`DeltaT=T_(2)-T_(1)=(85-30)^(@)C=55^(@)C`
specific heat of water `S =4.2 J g^(-1)^(@)C^(-1)`
The amount of heat used, `DeltaQ =msDelta`
`=4000xx4.2xx55=924000`
`=9.24xx10^(5) J mi n^(-1)`