Correct Answer - A
Given , `m=4xx10^(-2)kg =40 g. DeltaT=50^(c )`
Number of moles ,`n=(m)/(M)=(40)/(28)=1.43`
As nitrogen is a diatomic gas, molar specific heat at contstant pressure is
`C_(p)=(7)/(2)R=(7)/(2)xx8.3 J mol^(-1) K^(-1)=29.05 J mol^(-1) K^(-1)`
As `DeltaQ =nC_(p)DeltaT`
`DeltaQ=1.43xx29.05xx50=2.08xx10^(3)` J =2 2.08KJ