Question

If the coefficient of performance of a refrigerator is 5 and operates at the room temperature (`27^(@)` C), find the temperature inside the refrigerator.
A. 240 K
B. 250 K
C. 230 K
D. 260 K

Answer 1

Correct Answer - B
Here coefficient of performance `beta`=5
`t_(1)=27^(@)C=(27+273)K=300K`
As `beta =(T_(2))/(T_(1)-T_(2)), rArr 5 =(T_(2))/(300-T_(2))`
or `1500-5T_(2)=t_(2)or 6T_(2)=1500`
`therefore T_(2)=(1500)/(6)=250 K`