Question

A simple pendulum of length `4.9m` is immersed in a liquid of density `rho =0.4 kg//m^(3)`. Then the time period of pendulum is (density of bob `=0.8 kg//m^(3))`
A. `pi s`
B. `3pi s`
C. `2 pi s`
D. `pi//2s`

Answer 1

Correct Answer - A
`T = 2pi sqrt((l)/(g_(eff)))` where `g_(eff) = g (1-(rho)/(sigma))`