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Calculate the internal energy of 1 gram of oxygen at NTP.

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Calculate the internal energy of 1 gram of oxygen at NTP.
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Correct Answer - `177.2 J`
Here, ` T=0^(@)C = 273 K, R = 8.31 J mol^(-1) K^(-1)`
Internal energy of 1 mole of oxygen (diatomic gas) = `5/2 RT`
`:.` Internal energy of 1 gram of oxygen = `5/2 R/M T`
`=5/2 xx 8.31/32 xx 273 = 177.2 J`
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