Correct Answer - A
To have the equilibrium of simple harminic motion, it is best to represent simple harmonic motion as uniform circular motion.
At `t = 0`, let particle is making an angle `delta` with `-ve,x`-axis a shown, then `sin delta = (h)/(A) rArr delta = sin^(-2) ((h)/(A))`
At time, `y =- A sin (omegat = delta)`
So, the equation of simple harmonic motion is,
`y =- sqrt((mv_(0)^(2))/(k)+h^(2)) [sin[sqrt((k)/(m))t+sin^(-1)((h)/(A))]]`