Question

If `C_(1), C_(2), C_(3)`......are random speed of gas molecules, then average speed `C_(av)= (C_(1)+C_(2)+C_(3)+...C_(n))/(n)` and root mean square speed of gas molecules, `C_(rms) = sqrt((C_(1)^(2)+C_(2)^(2)+C_(3)^(2)+...C_(n)^(2))/(n)) =C`. Further , `C_(2) prop T or C prop sqrt(T)` at `0k, C=0`, ie., molecular motion stops. With the help of the passage given above , choose the most appropriate alternative for each of the following question:
`KE` per molecule of the gas in the above question becomes x times, where x is
A. `1/2`
B. `1/4`
C. 4
D. 2

Answer 1

Correct Answer - D
As, KE per molecule `prop T`
and T is doubled, therefore, kinetic energy per molecule becomes 2 times.