Question

A body weighing 10 kg is executing SHM, has a velocity of `6.0ms^(-1)`, after one second of starting from the mean position. If its time period is 6 second, find its K.E., P.E. and total energy.

Answer 1

Here, `m=10kg, V=6.0ms^(-1), t=1s, T=6s`
K.E.=`(1)/(2)mV^(2)=(1)/(2)xx10xx6^(2)=180J`
`V=aomegacosomegat=aomegacos((2pi)/(T))t` so `6=aomegacos (2pi)/(6)xx1=aomegaxx(1)/(2) or a omega=12`
T.E.`=(1)/(2)momega^(2)a^(2)=(1)/(2)xx10xx(12)^(2)=720J :.` P.E.`=` T.E.-K.E. `=720-180=540J`