Question

A block rests on a horizontal table which is executing SHM in the horizontal plane with an amplitude A. What will be the frequency of oscillation, the block will just start to slip? Coefficient of friction`=mu`.

Answer 1

Restoring force on the block `=momega^(2)A=mumg`.
`:.` Acceleration in the block `=mug`
Frequency of oscillation,
`v=(1)/(2pi)sqrt((ac c e l eration)/(displacement))=(1)/(2pi)sqrt((mug)/(A))`