Question

The displacement x of a particle moving in one dimension under the action of a constant force is related to time t by the equation `t=sqrt(x)+3`, where x is in meter and t is in second. Find the displacement of the particle when its velocity is zero.

Answer 1

`t=sqrt(s)+3impliessqrt(s)=t-3impliess=(t-3)^(2)=t^(2)-6t+9`
`s=t^(2)-6t+9`
`v=(ds)/(dt)=2t-6`
When velocity `v=0, 2t-6=0impliest=3`
`At t=3, s=0`