Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
95 views
in Physics by (76.5k points)
closed by
A partical is moving in a straight line under constant acceletation. If the motion starts from rest, Find the ratio of displacement in `n` second to that in the `n^(th)` second.
A. `(2n-1)/n^(2)`
B. `1/n`
C. `n^(2)/(n-1)`
D. `n^(2)/(2n-1)`

1 Answer

0 votes
by (76.7k points)
selected by
 
Best answer
Correct Answer - D
`s_(n)=1/2 a n^(2)`
`s_(nth)=1/2 a(2n-1)`
`s_(n)/s_(nth)=n^(2)/((2n-1))`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...