Question

A bullet fired into a fixed target loses half of its velocity after penetrating `1 cm`. How much further it will penetrate before coming to rest, assuming that it faces constant resistance to motion
A. `1.5 cm`
B. `1.0 cm`
C. `3.0 cm`
D. `2.0 cm`

Answer 1

Correct Answer - C

`A` to `B`: `(u/2)^(2)=u^(2)-2axx1`
`B` to `C: 0=(u/2)^(2)-2axxd`
From (i), `2a=(3u^(2))/4` in (ii)
`0=u^(2)/4 -(3u^(2))/4dimpliesd=3 cm`