Correct Answer - C
Let the first ball reaches the ground after time t, the second ball will take time `(t-2)`.
`80=1/2g t^(2)impliest=4 s`
Let u: initial velocity of the second ball
`80=u(t-2)+1/2g (t-2)^(2)`
`=u(4-2)=1/2xx10(4-2)^(2)`
`=2u+20`
`u=30 m//s`