Correct Answer - D
Refer to figure, Here the two springs are in series. Let the mass `M` be pulled through small distance `A` towards right hand side. Due to it, let `x_(1)` and `x_(2)` be the extension in two springs.
Here, the tnesion or the force is same for both the springs. So `k_(1)x_(1)=k_(2)x_(2)` or `x_(2=k_(1)x_(1)//k_(2)`.
Total extension, `A=x_(1)+x_(2)`
`=x_(1)+(k_(1)x_(1))/(k_(2))=x_(1)((k_(2)+k_(1))/(k_(2)))`
`:.` Amplitude of point `P=` extension of spring `k_(1)`
`=x_(1)=(k_(2)A)/(k_(1)+k_(2))`