Question

A stone is allowed to fall from the top of a tower 300 m height and at the same time another stone is projected vertically up from the ground with a velocity `100 m//s`. Find when and where the two stones meet?

Answer 1

Height of the tower `h=300m`
Suppose the two stones meet at a height x from Z
ground after t second
`t=(S_(r))/(u_(r)),u_(r)=u+0=u,S_(r)=h`
`t=(h)/(u)=(300)/(100)=3sec`
Height of the stone from the point of projection is
`X=ut-(1)/(2 g t^(2))=100xx3-(1)/(2)xx9.8xx9=255.9m`