Fig. shows the given set up.
Here, `R = PC = 20 cm`
`C_1 P = 30 cm, OC_1 = 25 cm`
As the final image due to the combination coincides with the object itself, the rays reflected from convex mirror must be retracting their path. This can happen only when rays refracted from convex lens tend to meet at centre of curvature of convex mirror. Therefore, for convex lens,
`v = C_1 C = C_1 P + PC = 30 + 20 = 50 cm`,
when `u = OC_1 = -25 cm`
From `(1)/(f)=(1)/(v)-(1)/(u)=(1)/(50)+(1)/(25)=(3 + 6)/(150)=(9)/(150)`
`f = 150//9 = 16.67 cm`.
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