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The accelerator of a train can produce a uniform acceleration of `0.25ms^(-2)` and its brake can produce a retardation of `0.5ms^(-2)` The shortest time in which the train can travel between two stations 8 km apart is x minuts and 10 s, if it stops at both stations. The value of x is.

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Correct Answer - 5
`t_(min)=[(2(alpha+beta)l)/(alphabeta)]^(1//2)v_(max)=((2alphabetal)/(alpha+beta))^((1//2)`
`t_(min)=sqrt(((0.25+0.5)8xx10^(3)xx2)/(0.25xx0.5))=310s=5min10s`

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