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The velocity-displacement for a for plane on a straight runway is shown in . Determine the speed and acceleration of the jet plane at `s=150 m`.
image.

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Referring to the `v -s` graph, its slope for `100 le s le 250` is equal to `(60 - 50)/(250 - 100) = (1)/(5)`
The equation of the above graph is given by `(v - 50)/(s - 100) = (1)/(15)`
This gives, `v = (650 + s)/(15), 100 le s le 250`.
Substituting `s = 150`,
we have `v = (160)/(3) m//s`
Since, `a = (vdv)/(ds) " and " (dv)/(ds) = (1)/(15) " for " 100 le s le 250`,
we have `a = (32)/(9) m//s^(2)`
image

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