Question

A particle moves vertically with an upward initial speed `v_(0) = 5 m//s`. If its acceleration varies with time as shwon in `a - t` graph in the fig. 4.30, find the velocity of the particle at `t = 7s`.

Answer 1

`v = v_(0) + Delta v`
`= v_(0) + A`,
where, `A = A_(+) + A_(-)`
`= (5 xx 1) + (-(1)/(2) xx 8 xx 6)`
`= -19`
and `v_(0) = +5`
Then, `v = 5 - 19 = - 14 m//s`