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An object is placed at a distance of `6 cm` from a convex mirror of focal length `20 cm`. Locate the position and nature of the image.

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Here, `u = -16 cm, f = + 20 cm, v = ?`
`(1)/(v)=(1)/(f)-(1)/(u)=(1)/(20)-(1)/(-16) = (16 + 20)/(320) = (36)/(320)`
`v = (320)/(36) = (80)/(9) = 8.9 cm`
As `v` is positive, therefore, image is virtual, erect and is formed behind the mirror.

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