The course of rays image formation is shown in Fig. Clearly, image `I` formed by plane mirror is such that `MI = OM = 24 cm`.
As convex mirror forms the image at `I` itself,
therefore, `v = PI = MI - MP`
=`MI - (OP - OM)`
=`24 - 12 = 12 cm`
`u = OP = -36 cm`
`(1)/(f)=(1)/(v)+(1)/(u) = (1)/(12)-(1)/(36) = (3 - 1)/(36) = (2)/(36) = (1)/(18)`
`f = 18 cm , R = 2 f = 2 xx 18 = 36 cm`.

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