Correct Answer - C
If `theta` is critical angle between the pair of media in contact, then from Fig.
`tan theta = (11.54//2)/(10) = 0.577`
`:. theta = 30^@`
Now `.^1 mu_2 = (1)/(sin theta) = (2.72)/(mu) = (1)/(sin 30^@) = 2`
`2 mu = 2.72, mu = 1.36`.
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