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Mass of the bob of a simple pendulum of length `L` is `m`. If the bob is projected horizontally from its mean position with velocity `sqrt(4 gL)`, then the tension in the string becomes zero after a vertical displacement of
A. `L//3`
B. `3L//4`
C. `4L//3`
D. `5L//3`

1 Answer

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Best answer
Correct Answer - D
`v = sqrt(g(3h-r))` , Where `h` is maximum height at which the tension in the string is zero.

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